q=s.+v.+vonsovskii.++translated+from+russian+by+ron+hardin.&searchType=standard&isFacet=true&view=standard&searchWay=author&rows=10&sortWay=score&sortOrder=desc&searchWay0=marc&logical0=AND
rows=10&searchWay0=marc&logical0=AND
S. V. Vonsovskii. Translated from Russian by Ron Hardin.