q=S.+V.+Vonsovskii.++Translated+from+Russian+by+Ron+Hardin.&searchType=standard&isFacet=true&view=standard&rows=10&sortWay=score&sortOrder=desc&searchWay0=marc&logical0=AND
rows=10&searchWay0=marc&logical0=AND
S. V. Vonsovskii. Translated from Russian by Ron Hardin.